includec 棋牌游戏源码

C语言实现的简单扑克牌游戏源码

扑克牌游戏是一种经典的桌面游戏,通常使用一副52张的扑克牌进行游戏，在本篇文章中，我们将使用C语言和MFC（Microsoft Foundation Classes）框架，开发一个简单的扑克牌游戏，游戏的主要功能包括：创建扑克牌、洗牌、发牌、玩家选择牌、比较牌面值、胜负判定以及重新洗牌等功能。

扑克牌游戏的基本概念

扑克牌游戏是一种基于概率和策略的娱乐活动,一副标准扑克牌包含52张牌，分为4种花色：黑桃、梅花、方块和红桃，每种花色有13张牌，分别代表数字1到13（其中1通常表示为A），扑克牌游戏的规则因具体游戏而异，但基本操作包括洗牌、发牌、选择牌和比较牌面值。

扑克牌游戏的实现过程

要实现扑克牌游戏,我们需要完成以下几个步骤：

1. 定义扑克牌的数据结构
2. 创建扑克牌库类
3. 实现洗牌、发牌和计算牌面值的方法
4. 设计游戏逻辑
5. 实现用户界面（可选）
6. 测试和优化

定义扑克牌的数据结构

在C语言中,我们可以定义一个结构体来表示一张扑克牌，结构体包含两个字段：点数（number）和花色（suit），点数可以是字符类型，花色也可以是字符类型。

typedef struct {
    char number;   // 点数，'A'到'K'
    char suit;      // 花色，'S'（黑桃）、'H'（方块）、'D'（梅花）、'C'（红桃）
} Card;

创建扑克牌库类

扑克牌库类用于管理扑克牌的创建、洗牌、发牌等操作，以下是扑克牌库类的定义：

#include <iostream>
class扑克牌库 {
private:
    int totalCards;  // 总牌数
    int currentCards; // 当前发过的牌数
    Card* deck;      // 扑克牌数组
public:
   扑克牌库(int total) {
        totalCards = total;
        currentCards = 0;
        // 初始化牌库
        deck = (Card*)malloc(total * sizeof(Card));
        for (int i = 0; i < total; i++) {
            char suit = 'S'; // 假设所有牌都是黑桃
            char number;
            switch(i % 13) {
                case 0: number = 'A'; break;
                case 1: number = '2'; break;
                case 2: number = '3'; break;
                case 3: number = '4'; break;
                case 4: number = '5'; break;
                case 5: number = '6'; break;
                case 6: number = '7'; break;
                case 7: number = '8'; break;
                case 8: number = '9'; break;
                case 9: number = '10'; break;
                case 10: number = 'J'; break;
                case 11: number = 'Q'; break;
                case 12: number = 'K'; break;
            }
            deck[i] = (Card){number, suit};
        }
    }
    // 洗牌方法
    void shuffle() {
        for (int i = 0; i < totalCards; i++) {
            int randomIndex = rand() % totalCards;
            Card temp = deck[i];
            deck[i] = deck[randomIndex];
            deck[randomIndex] = temp;
        }
    }
    // 发牌方法
    Card getCard() {
        if (currentCards >= totalCards) {
            printf("所有牌已经发完\n");
            return (Card){0, 0};
        }
        Card card = deck[currentCards];
        currentCards++;
        return card;
    }
    // 计算牌面值的方法
    int calculateValue(Card card) {
        if (card.number == 'A') {
            return 1;
        } else if (card.number == 'J') {
            return 11;
        } else if (card.number == 'Q') {
            return 12;
        } else if (card.number == 'K') {
            return 13;
        } else {
            return (int)card.number - (int)'0';
        }
    }
};

实现游戏逻辑

游戏逻辑主要包括以下功能：

• 用户选择要查看的牌
• 比较牌面值
• 判断胜负
• 重新洗牌

以下是游戏的主要逻辑实现：

#include <windows.h>
#include <conio.h>
void main() {
    int totalCards = 52;
   扑克牌库 deck(totalCards);
    deck.shuffle(); // 洗牌
    int currentCardIndex = 0;
    int playerValue, computerValue;
    printf("欢迎使用扑克牌游戏\n");
    printf("游戏规则：\n");
    printf("1. 您可以选择一张牌\n");
    printf("2. 比较牌面值\n");
    printf("3. 胜负判定\n");
    printf("4. 重新洗牌\n");
    printf("按任意键开始\n");
    getche();
    while (1) {
        // 显示当前牌
        printf("当前牌：");
        printf("%c %c", deck.getCard(currentCardIndex).number, deck.getCard(currentCardIndex).suit);
        printf("\n");
        // 用户选择要比较的牌
        printf("您选择要比较的牌（1-52）：");
        int choice;
        scanf("%d", &choice);
        if (choice < 1 || choice > totalCards) {
            printf("选择无效，请重新选择\n");
            continue;
        }
        // 获取用户选择的牌
        Card playerCard = deck.getCard(choice - 1);
        playerValue = deck.calculateValue(playerCard);
        // 计算计算机的牌面值
        int randomIndex = rand() % totalCards;
        Card computerCard = deck.getCard(randomIndex);
        computerValue = deck.calculateValue(computerCard);
        // 比较牌面值
        if (playerValue > computerValue) {
            printf("您获胜！\n");
        } else if (playerValue < computerValue) {
            printf("您输掉！\n");
        } else {
            printf("牌面值相等，游戏平局\n");
        }
        // 重新洗牌
        deck.shuffle();
        currentCardIndex = (choice == 1) ? 0 : currentCardIndex + 1;
    }
}

实现用户界面

为了提高游戏的交互性,我们可以使用MFC框架来创建一个简单的用户界面，以下是使用MFC实现的用户界面示例：

#include "windows.h"
#include "message.h"
#include "input.h"
#include "conio.h"
#include "wizard.h"
class gameWindow : public MFC {
private:
    int currentCardIndex;
   扑克牌库 deck;
public:
    gameWindow() : MFC("游戏窗口", 400, 300) {
        AddWindow();
        ShowWindow();
        Connect();
        message msg;
        msg.hook = &hook;
        msg.show();
    }
    void hook(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam) {
        if (msg == msgID主窗口) {
            switch(wParam) {
                case 1:  // 按下回车键
                    msg.show();
                    break;
            }
        }
    }
    void OnPaint() {
        // 绘制背景
        PAINTSTRUCT ps;
        GetWindowRect(GetDesktopWindow(), &ps);
        SetBkColor(&ps, RGB(255, 255, 255));
        // 绘制牌
        RECT rect(100, 100, 300, 200);
        SetFillStyle(SolidFill, White);
        MoveToPoints(&rect, &ps);
        LineToPoints(&rect, &ps);
        SetFillStyle(SolidFill, Black);
        MoveToPoints(&rect, &ps);
        LineToPoints(&rect, &ps);
        // 绘制当前牌
        int x = 150, y = 150;
        char cardNumber = deck.getCard(currentCardIndex).number;
        char cardSuit = deck.getCard(currentCardIndex).suit;
        // 绘制数字部分
        SetCharSet(Courier);
        SetWidth(12);
        MoveToPoints(&x, &y);
        LineToPoints(&x + 1, &y);
        MoveToPoints(&x + 1, &y);
        LineToPoints(&x + 2, &y);
        MoveToPoints(&x + 2, &y);
        LineToPoints(&x + 3, &y);
        MoveToPoints(&x + 3, &y);
        LineToPoints(&x + 4, &y);
        MoveToPoints(&x + 4, &y);
        LineToPoints(&x + 5, &y);
        MoveToPoints(&x + 5, &y);
        LineToPoints(&x + 6, &y);
        MoveToPoints(&x + 6, &y);
        LineToPoints(&x + 7, &y);
        MoveToPoints(&x + 7, &y);
        LineToPoints(&x + 8, &y);
        MoveToPoints(&x + 8, &y);
        LineToPoints(&x + 9, &y);
        MoveToPoints(&x + 9, &y);
        LineToPoints(&x + 10, &y);
        MoveToPoints(&x + 10, &y);
        LineToPoints(&x + 11, &y);
        MoveToPoints(&x + 11, &y);
        LineToPoints(&x + 12, &y);
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        LineToPoints(&x + 13, &y);
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